The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821
<h3>How to solve?</h3>
Given: currently has seven rackets of each version.
Then the probability that the next ten customers get the racket they want is P(3≤X≤7)
<h3>Why P(3≤X≤7)?</h3>
Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.
X ~ Binomial (n = 10, p = 0.6)
P(3≤X≤7) = P(X≤7) - P(X≤2)
From Binomial Table:
= 0.8333 - 0.012
= 0.821
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X =9 had the samw question on sat
It takes 8 dozens of flour.
5x4=20 so the person needs 4 times more than 2 dozens. 2x4=8 therefor, the person needs 8 dozens of flour.
Each peice is 1.5 inches
7*1.5=10.5
The dowel was 10.5 inches long
16² = 18² + 19² - 2(18)(19)cos(z)
256 = 324 + 361 - (684)cos(z)
256 = 685 - (684)cos(z)
-429 = -684cos(z)
cos(z) = -429/-684
z = cos⁻¹ (0.627)
z = cos⁻¹ (cos 51) [ Cos 51 = 0.627 ]
z = 51
In short, Your Answer would be: 51
Hope this helps!
