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Lisa [10]
3 years ago
15

The line for which equation has negative slope?

Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

B.

Step-by-step explanation:

To have a negative slope, <em>m</em> has to be negative. Any negative slope would show up as a negative coefficient in front of <em>x</em>.

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Need help with this question please.
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Answer:

The answer is, The fastest speed is 3/4 mile in 1/8 hour

Step-by-step explanation:

the answer i have = 6miles per hour and the rest of the answers are lower than that.

8 0
2 years ago
The metric system is based on multiples of 100. Please select the best answer from the choices provided A.True B.False
Otrada [13]

Answer:

true

Step-by-step explanation:

i think

5 0
3 years ago
If one line has a slope of 2/3, then the slope of a line parallel to it would be?
ipn [44]

-3/2

perpendicular slopes are those that are opposite sign and reciprocal of the original given slope

8 0
3 years ago
Last week rob ran 19 miles more than amy. Rob ran 33 miles. How many miles did amy run?
Elanso [62]

Answer:

14

Step-by-step explanation:

7 0
3 years ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
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