12000m=12km
3l=0.003cl
7000ml= 7l
1kg=1l
1100cl=11L
7000L = 7k
9cl=90ml
6g=600 cg
Answer:
(i) She gives each student a pretest. Then she teaches a lesson using a computer program. Afterwards, she gives each student a posttest. The teacher wants to see if the difference in scores will show an improvement.
Step-by- Step
The situation is a case of matched or paired samples since the samples are dependent. The two measurements are drawn from the same pair of individuals The parameter that is tested using matched pairs is the population mean and this is what teacher intends to use a hypothesis test for.
81=3^4
I hope this helps! Good luck!
Answer:
and ![H_{a}: \mu > 185](https://tex.z-dn.net/?f=H_%7Ba%7D%3A%20%5Cmu%20%3E%20185)
Step-by-step explanation:
The null hypothesis
states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form ![H_{0}: parameter = value](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20parameter%20%3D%20value)
In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form
.
The alternative hypothesis
states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms
![H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value](https://tex.z-dn.net/?f=H_%7Ba%7D%3A%20parameter%20%3E%20value%5C%5CH_%7Ba%7D%3A%20parameter%20%3C%20value%5C%5CH_%7Ba%7D%3A%20parameter%20%5Cneq%20value)
The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use
as his alternative hypothesis.