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jeyben [28]
3 years ago
12

(3m^4n^6)(2mn)^0(2m^2n)

Mathematics
1 answer:
laiz [17]3 years ago
5 0
(3m^4n^6) * (2mn)^0 * (2m^2n)\\
(3m^4n^6) * (2m^2n)\\
3 * 2 * m^4 * m^2 * n^6 * n\\
6 * m^{4+2}*n^{6+1}\\
6m^6n^7
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Jones Street is parallel to Lincoln Street, and both streets are intersected by Elm Street and Avenue A. Jones Street J 105° m E
kvv77 [185]

We have:

Alternate angles are equal in measure, therefore:

\angle E=105^{\circ}

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\begin{gathered} 105+\angle JEA+32=180 \\ 137+\angle JEA=180 \\ 137+\angle JEA-137=180-137 \\ \angle JEA=43 \end{gathered}

Answer: 43°

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Reasoning point F lies on EG and point M lies on EN. If F,E, and M are collinear, what must be true of these rays.
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