Answer:
hola:)
Step-by-step explanation:
3 ^6= 6x6x6
4 ^5= 4x4x4x4x4
6 ^3=3x3x3x3x3x3
5 ^4= 4x4x4x4x4
Divide the total amount of money Janice has by the cost of the stamps.
$7.20 / $0.30 = 24
Janice can buy 24 stamps.
Answer:
Step-by-step explanation:
Hello!
The objective is to compare the mean rating on the client satisfaction survey of two consultants A and B.
Consultant A
X₁: Rating on the client satisfaction survey given to consultant A
n₁= 16
X[bar]₁= 6.82
S₁= 0.64
Consultant B
X₂: Rating on the client satisfaction survey given to consultant B
n₂= 10
X[bar]₂= 6.25
S₂= 0.75
a. The claim is that consultant A, which is more experienced, has a higher average service rate than consultant B, which has less experience, then the hypotheses are:
H₀: μ₁ ≤ μ₂
H₁: μ₁ > μ₂
b. If both variables have a normal distribution and the population's variances are unknown but equal, the statistic for this test is a t-test for independent samples with pooled sample variance.
![t_{H_0}= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}](https://tex.z-dn.net/?f=t_%7BH_0%7D%3D%20%5Cfrac%7B%28X%5Bbar%5D_1-X%5Bbar%5D_2%29-%28Mu_1-Mu_2%29%7D%7BSa%2A%5Csqrt%7B%5Cfrac%7B1%7D%7Bn_1%7D%20%2B%5Cfrac%7B1%7D%7Bn_2%7D%20%7D%20%7D%20~~t_%7Bn_1%2Bn_2-2%7D)
![Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} = \frac{15*(0.64^2)+9*(0.75^2)}{16+10-2}= 0.47](https://tex.z-dn.net/?f=Sa%5E2%3D%20%5Cfrac%7B%28n_1-1%29S_1%5E2%2B%28n_2-1%29S_2%5E2%7D%7Bn_1%2Bn_2-2%7D%20%3D%20%5Cfrac%7B15%2A%280.64%5E2%29%2B9%2A%280.75%5E2%29%7D%7B16%2B10-2%7D%3D%200.47)
Sa= 0.68
![t_{H_0}= \frac{6.82-6.25-0}{0.68*\sqrt{\frac{1}{16} +\frac{1}{10} } }= 2.079](https://tex.z-dn.net/?f=t_%7BH_0%7D%3D%20%5Cfrac%7B6.82-6.25-0%7D%7B0.68%2A%5Csqrt%7B%5Cfrac%7B1%7D%7B16%7D%20%2B%5Cfrac%7B1%7D%7B10%7D%20%7D%20%7D%3D%202.079)
c. The p-value is the probability of obtaining a value as extreme as the value of the statistic. As the test it is one-tailed and has the same direction (right), symbolically:
P(t₂₄≥2.079)= 1 - P(t₂₄<2.079)= 1 - 0.9758= 0.0242
d. The p-value:0.0242 is less than α:0.05, then the decision is to reject the null hypothesis.
Using a significance level of 5%, there is significant evidence to say that the average service rate of consultant A is higher than the average service rate of consultant B.
I hope this helps!
Answer:
415.48
Step-by-step explanation:
is the area
Answer: ar·ith·met·ic pro·gres·sion
/ˌeriTHˌmedik prəˈɡreSH(ə)n/
noun
a sequence of numbers in which each differs from the preceding by a constant quantity (e.g., 3, 6, 9, 12, etc.; 9, 7, 5, 3, etc.).
the relationship between numbers in an arithmetic progression.
"the numbers are in arithmetic progression"
Step-by-step explanation: