Multiply entire equation by (x-2)(x+1) to get rid of the denominators That would lead to X(x+1)+(x-1)(x-2)=-1(x-2)(x+1)
Finally, using distributive property and foil, you would get x^2+x+x^2-3x+2=(-x^2+x+2).2x^2-2x+2=-x^2+x+23x^2-3x=0
3x(x-1)x=0 and x=1
Answer:
371.2
Step-by-step explanation:
Answer:
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Step-by-step explanation:
where is the question
A is the right answer i think
Adding a zero on the right changes the place value of all the other digits
