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3 years ago

9

Steven earns extra money babysitting. He charges $37.00 for 4 hours and $55.50 for 6 hours. Enter an equation to represent the r

elationship. Let x represent the number of hours Steven babysits and y represent the amount he charges.

2 answers:

Artist 52 [7]3 years ago

7 0

37+4x=55.50+6x....zzz

Mekhanik [1.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

3.2

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Naddik [55]

Answer:

I will

Step-by-step explanation:

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2 years ago

Your Numbers are; 25, 75, 50, 1, 9, 3 and your Target is 386 How do i get to 386 using only these numbers once and I can use Sub

GuDViN [60]

Answer:

You must order the operations in the way that it unfolds in the explanation;:

Step-by-step explanation:

(25 x 9) +75 + 50+ 9 x ( 3 + 1)

When performing the operations we have the following results:

(25 x 9) =225 +75= 300+50 = 350+9 = 359 x (3+1 )

Now we must solve the following: 359 x (4) = 386

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3 years ago

a triangle pyramid has lateral faces with bases of 6meters and hights of 9 meters the area of the base of the pyramid

Alexxandr [17]

What is the question

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3 years ago

What is the inverse of the function F(x)=x^2 <br><br> Please help me..

ikadub [295]

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Then solve for y:
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8 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago