Question

Graphingsolve a system of equation by graphing ​

Answer 1

SOLUTION:

$Point \ (1,3)$

Explanation:

Let's use the following System of Linear Equations in Two Variables in order to solve this exercise:

$\begin{array}{c}(1)\\(2)\end{array}\left\{ \begin{array}{c}y=2x+1\\y=-4x+7\end{array}\right.$

So we can graph these lines using two points.

For eq (1):

$y=2x+1 \\ \\ If \ x=0 \ then \ y=2(0)+1 \therefore y=1 \\ \\ If \ y=0 \ then \ 0=2x+1 \therefore x=-\frac{1}{2} \\ \\ \\ Points: \\ \\ (0,1) \\ \\ (-\frac{1}{2},0)$

So graph a line that passes through these two points. This is the red line shown below.

For eq (2):

$y=-4x+7 \\ \\ If \ x=0 \ then \ y=-4(0)+7 \therefore y=7 \\ \\ If \ y=0 \ then \ 0=-4x+7 \therefore x=\frac{7}{4} \\ \\ \\ Points: \\ \\ (0,7) \\ \\ (\frac{7}{4},0)$

So graph a line that passes through these two points. This is the blue line shown below.

The solution of this system of equation is the point of intersection, which is (1,3)

Learn more:

Parallel lines: brainly.com/question/12169569

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