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ycow [4]
2 years ago
14

I need to find the distance between pairs of integers like 8 and 32; 15 and 64; and -27 and 18. How do I do this?

Mathematics
1 answer:
Alona [7]2 years ago
5 0

Answer:

i believe you have to divide 8 by each number to get the distance between the pairs of integers.

Step-by-step explanation:

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Simplify 3(2 - c) - C​
kondor19780726 [428]

Answer:

6-3c-C

Step-by-step explanation:

3(2-c)-C

3(2)-3(c)-C

6-3c-C

7 0
3 years ago
Read 2 more answers
A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
A swimsuit is in sale for 45.50. if the sales price is discounted 5%from the orginal price. what was the original price. round t
AnnyKZ [126]
The answer is 42.80 , 2.28 is what they saved and i got the .80 cents because i rounded up from .78
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3 years ago
Determine the number of x-intercepts that appear on a graph of each function.
almond37 [142]

Answer:

not 2

Step-by-step explanation:

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2 years ago
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Solving Systems by Addition method
balandron [24]
-4x+0y=-8
=> x=2
substitute 2 into either function for y
it will come out the same and u will have solution
Note, if slopes or coefficient of x are the same => no solution because lines are parallel
Follow! and give me a brainliest plz
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3 years ago
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