Question

The Jones family plans a trip to the amusement park a purchase a family package for $128.00. They also want to buy lunch and souvenir cups. The chicken platter costs $8.50 each and the burger platter costs $9.50 each. The souvenir cups each cost $10.00, which included unlimited refills. Mr. and Mrs. Jones have a budget and are trying to decide who will order which platter and who will buy a souvenir cup. Let x represent the number of chicken platters, y represents the number of burger platters, and z represent the number of souvenir cups. Which of the following algebraic expressions can be used to describe the amount of money the Jones family will spend, before sales tax, based on the number of each meal and souvenir cups purchased?
A. 128 + 38( x + y + z)
B. 128( 8.50x + 9.50y + 10z)
C. 128 + 8.50x + 9.50y + 10z
D. 128 + x + y + z

Answer 1

Answer:

Option C - $128 + 8.50x + 9.50y + 10z$

Step-by-step explanation:

Given : The Jones family plans a trip to the amusement park a purchase a family package for $128.00. They also want to buy lunch and souvenir cups. The chicken platter costs $8.50 each and the burger platter costs $9.50 each. The souvenir cups each cost $10.00

To find : Which of the following algebraic expressions can be used to describe the amount of money the Jones family will spend, before sales tax, based on the number of each meal and souvenir cups purchased?

Solution :

Let x represent the number of chicken platters.

Let y represents the number of burger platters.

Let z represent the number of souvenir cups.

A family package cost is $128.00.

The chicken platter costs $8.50 each

The cost of x chicken platter = $8.50x$

The burger platter costs $9.50 each.

The cost of y burger platter = $9.50y$

The souvenir cups each cost $10.00

The cost of z souvenir cups  = $10z$

Therefore, Total they spend is $128 + 8.50x + 9.50y + 10z$

Hence, Option C is correct.

Answer 2

Answer is 

C. 128 + 8.50x + 9.50y + 10z

hope it helps