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ANTONII [103]
3 years ago
7

. Write a word problem that can be acted out using these counters.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
8 0
Please comment on this answer and give me a full question and I will be just fine answering it for you.
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how many ways can 8 distinguishable books be placed in 5 distinguishable shelves so that each shelf contains one book
musickatia [10]

There are 6720 ways by 8 distinguishable books be placed in 5 shelves.

According to statement

The number of books (n) is 8

The number of shelves (r) is 5

Now, we find the ways by which the 8 books be placed in 5 distinguishable shelves

From Permutation formula

P(n,r) = n! / (n-r)!

Substitute the values then

P(n,r) = 8! / (8-5)!

P(n,r) = (8*7*6*5*4*3*2*1) / (3*2*1)

P(n,r) = 8*7*6*5*4

P(n,r) = 6720

So, there are 6720 ways by 8 distinguishable books be placed in 5 shelves.

Learn more about PERMUTATION here brainly.com/question/11732255

#SPJ4

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