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Maslowich
2 years ago
8

A bag Contains five blue marbles two green marbles and three yellow marbles what is the probability of Choosing one Green marble

and a yellow marble with replacement what does this mean
Mathematics
1 answer:
Bad White [126]2 years ago
7 0

Answer:

3/50.

Step-by-step explanation:

There are 10 marbles in the bag.

Probability( a green marble) =  2/10 = 1/5.

Now we replace the green marble in the bag so it contains 10 marbles again.

Probabilty(a yellow marble) = 3/10.

So Probability(Choosing a green then a red with repeacemen)

= 1/5 * 3/10

= 3/50.

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Step-by-step explanation:

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If GF is a midsegment of CDE, find CD.<br><br> A. 3.4<br><br>B. 6.8 <br><br>C. 13.6 <br><br>D. 14
bogdanovich [222]

Answer:

C


Step-by-step explanation:

Triangle CGF and triangle CED are similar. Hence, the ratio of their corresponding sides are equal. Thus we can write:

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}

<em>We can now cross multiply and solve for CD:</em>

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}

Since GF is a midsegment of CDE, CD is double of CF. So we can write:

CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0

<em>By using quadratic formula \frac{-b+-\sqrt{b^2-4ac} }{2a} and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:</em>

\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2


<em>Since the expression for CD is \frac{15x^2+16x+3.2}{2x+3} , we plug in x=2 into this expression to find value of CD:</em>

\frac{15(2)^2+16(2)+3.2}{2(2)+3}=13.6

The correct answer is C

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3 years ago
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Step-by-step explanation:

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3 years ago
A group of 4 friends have a bag of 49 sweets. They divide the sweets equally between them. a) How many sweets does each friend g
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Answer:

a) Each friend gets 12 sweets

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Step-by-step explanation:

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