Answer:
The closest to the volume of cylinder is <u>63 in.³</u>.
Step-by-step explanation:
Given:
Cylinder with a height of 11 inches and a circumference of 8 1/2 inches.
Now, to find the volume.
As circumference is given we get the radius by putting formula:
Circumference = 8 1/2 inches = 17/2 inches.
Let the radius be 
<em>Taking the value of π = 3.14.</em>


<em>Dividing both sides by 6.28 we get:</em>

So, radius = 1.35 inches.
Height = 11 inches.
Now, putting the formula to get the volume:





<u><em>Hence, the volume of cylinder = 63 inches³ (approximately).</em></u>
Therefore, the closest to the volume of cylinder is 63 in.³.
Step-by-step explanation:
a. The mean can be found using the AVERAGE() function.
x = 272.7
b. The standard deviation can be found with the STDEV() function.
s = 39.9
c. The t-score can be found with the T.INV.2T() function. The confidence level is 0.04, and the degrees of freedom is 26.
t = 2.162
d. Find the lower and upper ends of the confidence interval.
Lower = 272.7 − 2.162 × 39.9 = 186.5
Upper = 272.7 + 2.162 × 39.9 = 358.9
Answer:
V'(t) = 
If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.
Step-by-step explanation:
Given:
V =
, where 0≤t≤40.
Here we have to find the derivative with respect to "t"
We have to use the chain rule to find the derivative.
V'(t) = 
V'(t) = 
When we simplify the above, we get
V'(t) = 
If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.
Answer:
Step-by-step explanation:
y - 4 = -5(x + 1)
y - 4 = -5x - 5
y = -5x - 1