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Lena [83]
3 years ago
7

Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y

our feet and the floor if you are not to slide.
Mathematics
1 answer:
umka21 [38]3 years ago
4 0

Friction force and train accelerating force are opposite in direction and equal in magnitude. Therefore m x a = u x m x g

As the mass is same, hence both are cancel out and remaining equation is

a = u x g

It’s given that a = 0.20g, so

0.20g = u x g

Cancel “g” on both sides;

0.20 = u

<span>Thus the coefficient of static friction = u = 0.20</span>
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Which statement best describes the area of Triangle ABC shown below?
sergeinik [125]

Answer:

  It is one-half the area of a rectangle with sides 4 units × 3 units

Step-by-step explanation:

One side of the triangle is on the line y = 2 between points x=2 and x=6. So, that side has length 6-2 = 4.

The opposite vertex has y-value 5, so is 3 units away from the line y = 2.

The area of the triangle can be considered to have a base of 4 and a height of 3. In the formula ...

  A = (1/2)bh

we find the area to be ...

  A = (1/2)×(4 units)×(3 units) . . . . triangle area

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A rectangle's area is the product of its length and width. So, a rectangle that is 4 units by 3 units will have an area of ...

  A = (4 units)×(3 units) . . . . rectangle area

Comparing the two area formulas, we see that the triangle area is 1/2 the area of the rectangle with sides 4 units × 3 units.

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3 years ago
Somone explain this question to me ? And help me do it
vlabodo [156]
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3 0
2 years ago
Find each percent of change. Round yo the nearest whole percent if necessary. <br><br> 55 to 35
Reptile [31]
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8 0
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Read 2 more answers
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
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