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Anit [1.1K]
3 years ago
12

What is the solution to the system of equations?

Mathematics
1 answer:
Leto [7]3 years ago
5 0

Answer:

  1. (x, y) = (8, -1)
  2. (x, y) = (7, 10.5)

Step-by-step explanation:

1. You can use the expression for y to substitute into the first equation:

  2x +4(1/4x -3) = 12

  2x +x -12 = 12 . . . . . . eliminate parentheses

  3x = 24 . . . . . . . . . . . add 12; next divide by 3

  x = 8 . . . . . matches choice C

__

2. You can use the expression for y to substitute into the second equation:

  x -2(2x -3.5) = -14

  -3x +7 = -14 . . . . . . eliminate parentheses

  21 = 3x . . . . . . . . . . add 3x+14; next divide by 3

  7 = x . . . . . matches the third choice

_____

When the answer choices are sufficiently different, you only need to find one value to determine which is the correct choice. (If you want to check your work further, you can substitute the other answer value into the two equations to see if it works.)

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Answer:

<u>f(x)=x²-2x-2</u>

Step-by-step explanation:

<em><u>f(x)=ax²+bx+c</u></em>

f(0)=-2 => c= -2

f(1)= -3=> a+b-2=-3; a+b=-1

f(2)= -2; 4a+2b-2=-2; 4a+2b=0; 2a+b=0

a+b=-1 and 2a+b=0

2a+b-(a+b)=0+1=> a=1

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f(x)=x²-2x-2

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3 years ago
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Answer:

A y= -3/4+6

Step-by-step explanation

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72 divided by X equals X
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Answer:72 divided by 9 equals 8

Step-by-step explanation:9 x 8=72

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Answer:

(2x100,000)(7x10,000)(9x100)(5x10)

Step-by-step explanation:

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Solve cosθ-cos2θ+cos3θ-cos4θ=0
Alik [6]

Answer:

  • θ = (2/5)πk or π(k +1/2) . . . . . for any integer k

Step-by-step explanation:

We can make use of the identities ...

  \cos{\alpha}-\cos{\beta}=-2\sin{\dfrac{\alpha+\beta}{2}}\sin{\dfrac{\alpha-\beta}{2}}\\\\\sin{\alpha}+\sin{\beta}=2\sin{\dfrac{\alpha+\beta}{2}}\cos{\dfrac{\alpha-\beta}{2}}

These let us rewrite the equation as ...

  0=\cos{\theta}-\cos{2\theta}+\cos{3\theta}-\cos{4\theta}\\\\0=-2\sin{\dfrac{\theta+2\theta}{2}}\sin{\dfrac{\theta-2\theta}{2}}-2\sin{\dfrac{3\theta+4\theta}{2}}\sin{\dfrac{3\theta-4\theta}{2}}\\\\0=2\sin{\dfrac{\theta}{2}}\left(\sin{\dfrac{3\theta}{2}}+\sin{\dfrac{7\theta}{2}}\right)\\\\0=4\sin{\dfrac{\theta}{2}}\sin{\dfrac{3\theta+7\theta}{4}}\cos{\dfrac{3\theta-7\theta}{4}}\\\\0=4\sin{\dfrac{\theta}{2}}\sin{\dfrac{5\theta}{2}}\cos{\theta}

The solutions are the values of θ that make the factors zero. That is, ...

  θ = 2πk . . . . for any integer k

  θ = (2/5)πk . . . . for any integer k (includes the above cases)

  θ = π(k +1/2) . . . . for any integer k

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4 years ago
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