(x-4y)(x-2y) product

Mathematics

1 answer:

son4ous [18]3 years ago

6 0

X^2-6xy+8y^2 I believe is the answer, I hope this helps!

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If PΔERO = 68 units and ΔERO has ER = x units, RO = 2x units, and EO = 3x units, what is the length of EO?

Artist 52 [7]

Answer:

34 units

Step-by-step explanation:

The perimeter of a triangle is given by the sum of the lengths of its three sides.

So if the perimeter is 68 units and the sides measure x, 2x and 3x, we have that:

x + 2x + 3x = 68

6x = 68

x = 68/6 units

Now with the value of x we can find the length of EO:

EO = 3x

EO = 3 * (68/6)

EO = 68/2 = 34 units

6 0

3 years ago

Christopher mixes the letters s, e, l, e, c, t, e, and d thoroughly. without looking, allen draws one letter. expressed as a fra

natka813 [3]

There are 8 letters and 3 of them is a vowel.

P(not consonant) = P(vowel) = 3/8
A is the correct choice.

7 0

3 years ago

Read 2 more answers

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$