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BaLLatris [955]
3 years ago
5

Three of the choices are unit rates for the price of milk. which choice is not?$1.00 per 8 ounces$1.30 per pint$3.47 per gallon$

2.80 per quart
Mathematics
1 answer:
Sedbober [7]3 years ago
7 0
$1.00 per 8 ounces, since it isn't in the simplest form (which isn't a unit rate)
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Name the kind or kinds of symmetry the following figure has: A
denpristay [2]
It is a straight line of symmetry because if you have a paper A and you fold it, it will form a straight line, and that is also meaning a straight line of symmetry. If you fold it any other way, it will not be a line of symmetry.

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6 0
3 years ago
Fran reads 54 pages per hour Darnell reads 60 pages per hour if they both read for 2.5 hours how many more pages will Darnell Re
spin [16.1K]
Hey You! Here's How To Solve This Question:


STEP 1:

60 × 2.5 = 150


STEP 2:

54 × 2.5 = 135


STEP 3:

150 - 135 = 15


So, Darnell read 15 more pages than Fran.

I Really Hope My Answer Helped You!
7 0
3 years ago
Im in need of a big brain
stiv31 [10]

Answer:

x = 34

Step-by-step explanation:

If it is bisected, that means the angles are equal <ABD = < CBD

The triangles are equal by SAS

That means AD = CD

2x+30 = 3x-4

subtract 2x from each side

2x+30 -2x = 3x-4 -2x

30 = x-4

Add 4 to each side

3x+4 = x-4+4

34 =x

8 0
2 years ago
Maryam wants to make a jug of juice
djyliett [7]

Answer:

sounds delicious lol

Step-by-step explanation:

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3 years ago
What is the exact area and arc length of these sectors? Please helppp
Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = \frac{90}{360} \times \pi \times 12^2 = 36\pi

2. Area of sector 2 = \frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi

3. Area of sector 3 = \frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi

4. Area of sector 4 = \frac{270}{360} \times \pi \times 6^2 = 27 \pi

5. Arc length of sector 1 = \frac{90}{360} \times 2 \times \pi \times 12 = 6\pi

6. Arc length of sector 2 = \frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi

7. Arc length of sector 3 = \frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi

8. Arc length of sector 4 = \frac{270}{360} \times 2 \times \pi \times 6 = 9\pi

4 0
3 years ago
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