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2 years ago

29. (09.04 MC)

Mathematics

1 answer:

lara [203]2 years ago

7 0

Answer:

The center is located at (-1, -2), and the radius is 5.

Step-by-step explanation:

The general equation of a circle is given as

(x - a)^2 + (y - b)^2 = r^2

where

a and b are the centre of the circle and r is the radius

Given the equation

x2 + 2x + y2 + 4y = 20

add 1 ad 4 to both sides

x2 + 2x + 1 + y2 + 4y + 4 = 20 + 4 + 1

factorise

(x +1)^2 + (y+2)^2 = 5^2

comparing with the general equation

a = -1, b = -2, r = 5 (all measured in units)

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WITCHER [35]

Answer:

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Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

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Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

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$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

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$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

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$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

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