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2 years ago

29. (09.04 MC)

Mathematics

1 answer:

lara [203]2 years ago

7 0

Answer:

The center is located at (-1, -2), and the radius is 5.

Step-by-step explanation:

The general equation of a circle is given as

(x - a)^2 + (y - b)^2 = r^2

where

a and b are the centre of the circle and r is the radius

Given the equation

x2 + 2x + y2 + 4y = 20

add 1 ad 4 to both sides

x2 + 2x + 1 + y2 + 4y + 4 = 20 + 4 + 1

factorise

(x +1)^2 + (y+2)^2 = 5^2

comparing with the general equation

a = -1, b = -2, r = 5 (all measured in units)

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Naily [24]

Answer:

$\displaystyle y = x^{-\frac{2}{3}}$

Step-by-step explanation:

Logarithms

Some properties of logarithms will be useful to solve this problem:

1. $\log(pq)=\log p+\log q$

2. $\displaystyle \log_pq=\frac{1}{\log_qp}$

3. $\displaystyle \log p^q=q\log p$

We are given the equation:

$\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }$

Applying the second property:

$\displaystyle \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}$

Substituting:

$\displaystyle \log_{2}(x) = 3\log_{2}(xy)$

Applying the first property:

$\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))$

Operating:

$\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)$

Rearranging:

$\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)$

Simplifying:

$\displaystyle -2\log_{2}(x) =3\log_{2}(y)$

Dividing by 3:

$\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}$

Applying the third property:

$\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)$

Applying inverse logs:

$\boxed{y = x^{-\frac{2}{3}}}$

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