Question

the legs of a right triangle have lengths of 28 meters and 21 meters. the hypotenuse has a lenght of 5x meters. what is the value of x

Answer 1

From the Pythagorean Theorem, we know that a^2+b^2=c^2
28^2+21^2=(5x)^2
784+441=25x^2
1225=25x^2
49=x^2
x=7
The length of the hypotenuse would be 35m.

Answer 2

$a=21 \ m , \ b=28 \ m , \ c=5x \ m \\ \\c^2 =a^2 + b^2\\ \\(5x)^2 =21^2 + 28^2\\ \\25x^2=441+784\\ \\25x^2=1225/:25\\ \\x^2=49\\ \\x=\sqrt{49}\\ \\x=7 \ m$