Answer:
"public static void passAList(ArrayList<Integer> myList, int[] intArr)", is the correct answer for the above question.
Explanation:
Missing information :
- The option is missing but the question states "choose from the following". The correct defining syntax is defined above.
Detailed Explantion :
- The above question asked about syntax which takes the value of list and array as an argument.
- It is already defined in the above syntax.
- And the value is passed by the user at the time of function call.
- The array list is defined by the help of the ArrayList class and the array is defined by the help of the "[]" symbol.
Whatever energy the electrons have when they come out of one terminal of the battery, they completely use it up on their way around the circuit, and they stagger back into the other terminal of the battery totally exhausted, with no energy left.
If each coulomb of electrons has 6 joules of energy when they leave the battery, then that's the energy they'll give up to the circuit before they return to the battery.
For each coulomb of charge that moves through that circuit, each flashlight bulb
will take 3 joules of energy away from that coulomb, and turn the energy into heat
and light.
==> 2 bulbs, 3 joules per coulomb that flows through each bulb, total 6 joules
per coulomb that flows around the circuit.
Note:
The question says that the bulbs are in series, but that wasn't necessary.
The energy consumed by the bulbs would be the same if they're in parallel.
A cool extra factoid:
The battery gives each coulomb of electrons that leaves it 6 joules of energy.
There's a special name for "1 joule per coulomb of charge". That's the "<em>volt</em>".
A battery that gives each coulomb of charge 6 joules of energy is a 6-volt battery.
Answer: dependents
Explanation: a person who relies on another, especially a family member, for financial support is a dependent
Answer:
The program code is at explaination
Explanation:
Below is the Python Function;
def check_halves(s):
# exact half not possible condition
if len(s)%2!=0:
return 0
halflen=len(s)//2
s1=s[:halflen]
s2=s[halflen:]
#null string condition
if len(s1)==0 or len(s2)==0:
return 0
#checking 1st digit of string recursively
if s1[0]==s2[0]:
return 1+check_halves(s1[1:]+s2[1:])
else:
return 0
You will find the input and output ad attachment.