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kakasveta [241]
3 years ago
9

A large drain and a small drain are opened to drain a pool. The large drain can empty the pool in 2 h. After both drains have be

en open for 1 h, the large drain becomes clogged and is closed. The small drain remains open and requires 10 more hours to empty the pool. How long would it have taken the small drain, working alone, to empty the pool?
Mathematics
2 answers:
erma4kov [3.2K]3 years ago
6 0

Answer:

22

Step-by-step explanation:

i did that before

Over [174]3 years ago
5 0

Answer:

22

Step-by-step explanation:

Let X be the time for only a small drain, the work completed would be unity.

 The small drain has been open for a total of 11 hours, one hour next to the large one, and 10 hours alone.

We have that large drainage can accomplish this in 2 hours.

We have the following system:

1/2 + 11 / x = 1

solving, we have:

11 / x = 1 - 1/2

11 / x = 1/2

x = 11 * 2

x = 22

I mean it would take a total of 22 hours for the small drain alone

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60 = 20/2 x H

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Can some one help me find x?
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2 years ago
Can someone help me with this?
Roman55 [17]

Answer:

Step-by-step explanation:

We first need to figure out how much money Jackie has since Pilar has the same amount of money, but in different coins. Jackie has 24 dimes and 13 quarters, so the amount of money is $2.40 + $3.25 = $5.65; therefore, Pilar has $5.65 also. In order to determine how many nickels and quarters Pilar has, we have to have a system of equations. It's up to us to write the equations we need to solve this. The first equation has to do with the NUMBER of coins Pilar has, the second has to do with the VALUE of each coin. We know that Pilar has only nickels and quarters and that she has a total of 53 coins. So the NUMBER equation is

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