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beks73 [17]
3 years ago
15

Write the ratio as a fraction in simplest form which whole numbers in the numerator and denominator 42 : 18

Mathematics
1 answer:
swat323 years ago
3 0

Answer:

7/3 or 2 1/3

Step-by-step explanation:

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Im going to give 10 points for this question please answer it
german
57 but it is an estimate because of the 4  so your answer is 57.4
8 0
3 years ago
Amira wrote the inequality p + 5 = 18. Which situation is best represented by this inequality?
Andreas93 [3]

Answer: Amira added 5 candy bars to the p pile of candy bars there were no more than 18 candy bars in the pile.

Step-by-step explanation: hope this helps

6 0
3 years ago
The half-life of a radioactive element is five years. A scientist has 18 grams of the element. The equation
lianna [129]

Answer:

The equation that describes the amount of mass left after a time t of a radioactive isotope is the following:

where

is the mass of the sample at t = 0

is the half-life of the sample

For the element X in this problem,

We want to find the time t at which

So we need to re-arrange the equation making t the subject:

Step-by-step explanation:

7 0
3 years ago
(Please Help For Examination) A sweet stall was placing order for making cardboard boxes for packing their sweets. Two sizes of
frozen [14]
Answer: Rs 2,184

Explanation:

1) The statement is incomplete. The complete statement contains the information of the dimensions of both bigger and smaller cardboard boxes.

2) The dimesions of bigger cardboard boxes are 25cm * 20 cm * 5 cm

3) The dimensions of smaller cardboard boxes are 15 cm * 12 cm * 5cm

4) For bigger cardboard boxes:

length, l = 25 cm
width, w = 20 cm
height, h = 5 cm

surface of each bigger carboard box = 2 [ l*w + l*h + w*h] = 2 [25*20 + 25*5 + 20*5] cm^2 = 1450 cm^2

total surface of 250 bigger cardboard boxes = 250 * 1450 cm^2 = 3625,500 cm^2

5% of the total surface area extra = 362,500cm^2 * 5 / 100 = 18,125 cm^2

Total area for bigger cardboard boxes= 362,500 cm^2 +  18,125 cm^2 = 380,625 cm^2

5) Smaller cardboard boxes

length, l = 15 cm
width, w = 12 cm
height, h =  5 cm

surface of each smaller cardboard box = 2 [l*w + l*h + w*h] = 2 [ 15*12 + 15 * 5 + 12 * 5] cm^2 = 630 cm^2

total surface of 250 smaller cardboard boxes = 250 * 630 cm^2 = 157,500 cm^2

5 % extra = 157,500 cm^2 * 5 / 100 = 7,875 cm^2

total area for smaller cardboard boxes = 157,500 cm^2 + 7,875 cm^2 = 165,375 cm^2

6) total area of cardboard required  = 380,625 cm^2 + 165,375 cm^2 = 546,000 cm^2

7) Cost of cardboard required

unit cost per area * total area = (Rs 4 / 1000cm^2) * 546,000 cm^2 = Rs 2,184.

Answer: Rs 2,184
7 0
4 years ago
What is the student’s error?
amm1812

Answer:

The answer to the question is 10a√2a(b + 2)

Step-by-step explanation:

To know the student's error, let us calculate the perimeter from the the start.

Dimension of the rectangle is given below:

√(50a³b²) and √(200a³)

Perimeter of a rectangle = 2(L + B) = 2L + 2B

2√(50a³b²) + 2√(200a³)

2 x 5ab√2a + 2 x 10a√2a

10ab√2a + 20a√2a

Factorise

10a√2a (b + 2)

Therefore, the student made an error by adding 10ab√2a and 20a√2a together.

Note: we can not add 10ab√2a and 20a√2a together since b is missing in one of the expression.

Therefore, the answer to the question is 10a√2a(b + 2).

5 0
3 years ago
Read 2 more answers
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