2. By selling an article for ₹1636.25, a dealer gains ₹96.25. Find his gain percentage.

Jim needs to rent a car. A rental company charges $21.00 per day to rent a car and $0.10 for every mile driven.

Ulleksa [173]

Answer:

$21d+25\leq 115$

Max is 4 days.

Step-by-step explanation:

An inequality is a math statement with more the one solution. The solution has a range of values for which the inequality can be satisfied. It has the same following components as an equation: variables and operations. However, the equal sign is replaced by an inequality sign: $,\leq,\geq$ .

We start by choosing a variable for an unknown value. Here is it the number of days he rents the car. We choose d.

We know he rents it for $21 pr day or 21d for any number of days. We also know her will drive 250 miles at $0.10 per mile or 0.10(250). We will combine the two into an expression.

21d + 0.10(250)

We know his limit is $115. This means he can rent the car for any number of days until he reaches $115. The charge must be less than or equal to 115.

So we write $21d+0.10(250)\leq 115$ .

To find the number of days he can rent the car, we solve for d using inverse operations.

$21d+0.10(250)\leq 115\\21d+25\leq 115\\21d+25-25\leq 115-25\\21d\leq 90\\\frac{21d}{21} \leq \frac{90}{21}\\d\leq 4.3$

This means Jim can rent the car up to 4 days. The 5th day will put the cost over $115.

3 0

3 years ago

What is the answer to, (4-1) . n = n . _

NikAS [45]

Answer:

(4-1)•n=n•(4-1)

Step-by-step explanation:

It should equal each other so no matter what n equals it will equal each other :3

4 0

3 years ago

Read 2 more answers

Motorola used the normal distribution to determine the probability of defects and the number

vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

$\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z$

Total defects=Production*Probability

=0.3174*1000

$=317.4$

b. $\mu=10,\sigma=0.05$

therefore:-

$z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z$

Defects=Probability*Production

=0.0026*1000

=2.6

c.Reducing process variation results in a significant reduction in the number of unit defects.

3 0

3 years ago

here are some numbers: 8, 11, 13, 18, 25, 37 8, 13 , 18 is an arithmetic progression and the rule is to add 5 use three of the n

Yuliya22 [10]

Answer:

Progression: 11, 18, 25

Rule: Add 7

Step-by-step explanation:

Given

List of numbers: 8, 11, 13, 18, 25, 37

Sample Progression: 8, 13, 18; with common difference of 5

Required

Form a different progression using any three listed numbers

To solve this; we'll make use of trial and error methods;

<em>NB: I've tried several numbers; So, I'll just stick to the one that works</em>

To start with;

Select ->11

Add 7 to 11: 11 + 7 - > 18

Add 7 to 18: 18 + 7 -> 25

With the above illustration, we've successfully used three numbers (11, 18 and 25) to form a new progression and the rule is to add 7

5 0

3 years ago

What’s 50 1/3+ 50 1/3?

slega [8]

Answer:

100 2/3

Step-by-step explanation:

50+50=100

1/3+1/3=2/3

100+2/3= 100 2/3

4 0

3 years ago

Read 2 more answers

2. By selling an article for ₹1636.25, a dealer gains ₹96.25. Find his gain percentage. ​

2. By selling an article for ₹1636.25, a dealer gains ₹96.25. Find his gain percentage.