To find the average rate of change of given function f(x) on a given interval (a,b):
Find f(b)-f(a), b-a, and then divide your result for f(b)-f(a) by your result for b-a:
f(b) - f(a)
------------
b-a
Here your function is f(x) = x^2 - 2x + 3. Substituting b=5 and a=-2,
f(5) = 5^2 -2(5)+3 =? and f(-2) = (-2)^2 - 2(-2) + 3 = ?
Calculate f(5) - [ f(-2) ]
------------------ using your results, above.
5 - [-2]
Your answer to this, if done correctly, is the "average rate of change of the function f(x) = x^2+2x+3 on the interval [-2,5]."
Answer:
9 x -50 or -9 x 50
Step-by-step explanation:
Answer:
the answer simplifying the question is. -1.8f - 16
Answer:
6!=720
3! • 2!=12
Step-by-step explanation:
We must recall that the factorial of a number n (positive or zero) is the product of all the integers from n down to 1
n!= n(n-1)(n-2)...1
Let's evaluate the given expressions
6!=6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1=720
Similarly
3!\cdot 2!=(3\cdot 2\cdot 1)\cdot (2\cdot 1)=6\cdot 2=12
Finally
\displaystyle \frac{6!}{3!}=\frac{6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{3\cdot 2\cdot 1}
\displaystyle \frac{6!}{3!}= \frac{720}{6}=120