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2 years ago

The point (2,-3) lies in quadrant

Mathematics

2 answers:

Sonbull [250]2 years ago

6 0

Answer:

The point (2,-3) lies in Quadrant 4

Step-by-step explanation:

In the top right of the graph is quadrant 1. In the top left of the graph is quadrant 2. In the bottom left of the graph is quadrant 3. And last but not least, the bottom right of the graph is quadrant 4.

Novay_Z [31]2 years ago

4 0

Hello there!

The point (2,-3) would lay in quadrant IV, or 4.

Basically:

Points that are (x, y) or positive x and positive y ay in quadrant 1, or I.

Points that are (-x, y) or negative x and positive y lay in quadrant 2, or II.

Points that are (-x, -y) or negative x and negative y usually lay in quadrant 3, or III.

Points that are (x, -y) or positive x and negative y usually lay in quadrant 4, or IV.

I hope this was helpful! Have a great rest of your day :)

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Jensen is building a snow fort. Each block in the fort weighs about 1 kilogram. Jensen hopes to make about 40 blocks for the for

babymother [125]

Answer: 13,333 snowflakes

Step-by-step explanation:

For this exercise let be "x" represents the number of snowflakes that will be in the fort.

According to the information given in the exercise, the weight of one block is 1 kilogram. Knowing that the fort must have 40 blocks, the total weight is:

$total\ weight=(1\ g)(40)\\\\total\ weight=40\ g$

Since each snowflake weighs $3* 10^{-3}$ grams, need to divide the total weight calculated above by the weight of a snowfake.

Therefore, through this procedure you get the following result:

$x=\frac{40\ grams}{3 * 10 ^{-3}\ grams}\\\\x\approx13,333$

Therefore, the there will be 13,333 snowflakes in the fort.

5 0

3 years ago

Someone pls help me solve this ;-;

Mazyrski [523]

5∛x + 4 = 44
5∛x = 40
∛x = 8
x = 8^3
x = 512

answer
C. 512

8 0

3 years ago

ANSWER PLZ QUICK AND FAST

stich3 [128]

Subtract 9 from both sides

7 0

3 years ago

Read 2 more answers

If g(x)=|x-3|, find the values of g(3) and g(-3)

agasfer [191]

Plug in what ever value is the function of g for x and solve:
g(3) = |3-3| = |0| = 0
g(-3) = |(-3)-3| = |(-6)| = 6

Hope this helps :)

5 0

3 years ago

Evaluate the integral

Kruka [31]

Hello, please consider the following.

$\displaystyle \begin{aligned} \int\limits^x {5sin(5t)sin(t)} \, dt &= -\int\limits^x {5sin(5t)} \, d(cos(t))\\ \\&=-[5sin(5t)cos(t)]+ \int\limits^x {25cos(5t)cos(t)} \, dt\\\\&=-5sin(5x)cos(x)+ \int\limits^x {25cos(5t)} \, d(sin(t))\\ \\&=-5sin(5x)cos(x)+[25cos(5t)sin(t)]+ \int\limits^x {25sin(5t)sin(t)} \, dt\\\\&=-5sin(5x)cos(x)+25cos(5x)sin(x)+ \int\limits^x {(25*5)sin(5t)sin(t)} \, dt\end{aligned}$

And we can recognise the same integral, so.

$\displaystyle (25-1)\int\limits^x {5sin(5t)sin(t)} \, dt= +5sin(5x)cos(x)-25cos(5x)sin(x)$

And then,

$\displaystyle \Large \boxed{\sf \bf\int\limits^x {5sin(5t)sin(t)} \, dt=\dfrac{5sin(5x)cos(x)-25cos(5x)sin(x)}{24}+C}$

Thanks

3 0

2 years ago

The point (2,-3) lies in quadrant​

The point (2,-3) lies in quadrant