Answer: A. 0.0164
Step-by-step explanation:
Given : The lengths of human pregnancies are normally distributed with a mean 
Standard deviation : 
Let X be the random variable that represents the length of pregnancy of a randomly selected human .
z-score : 
For X = 300

Now, the probability that a pregnancy last at least 300 days will be :-

Hence, the probability that a pregnancy last at least 300 days =0.0164
Answer:
m=-10
Step-by-step explanation:
just to make this easier ill subtract 2 from each side to get
2/3m = 1/6m -5
now multiply each side by 6 to get rid of denominators (this just makes it easier)
now in the next steps we simplify
4m = 1m -30
3m= -30
m=-10
Ok so first find the factors for 56 and 96
Hope that helps u get started :)
HOPE IT WILL HELP U.......