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Schach [20]
3 years ago
11

I need help with this pls be nice and tell me the answer :)

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0
M=-10 the first guy was correct
KIM [24]3 years ago
7 0

Answer:

m=-10

Step-by-step explanation:

just to make this easier ill subtract 2 from each side to get

2/3m = 1/6m -5

now multiply each side by 6 to get rid of denominators (this just makes it easier)

now in the next steps we simplify

4m = 1m -30

3m= -30

m=-10

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I don't understand how to do this problem.
Delicious77 [7]
Answers: 

x = 4
EF = 14
CF = 7
EC = 7

-------------------------------------------------------------
-------------------------------------------------------------

Work Shown:

C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent. 

Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4

Now that we know that x = 4, we can use this to find EC and CF

Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7

Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7

As expected, EC = CF (both are 7 units long).

By the segment addition postulate, we can say EC+CF = EF

EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
8 0
3 years ago
**FIRST CORRECT ANSWER GETS BRAINLEST**
puteri [66]

Answer:

C.) y = 5/4 x

Step-by-step explanation:

5/4 multiplied by 0.4 is 0.5

7 0
3 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
3 years ago
If 3lbs costs 4.00$ how much will 2 lbs cost
harkovskaia [24]

Answer:

1.5

Step-by-step explanation:

if you do 3 divided by 4 then you get 0.75 then you have to do 0.75 times 2 and you get 1.5 dollars for 2 pounds

3 0
3 years ago
Read 2 more answers
Can someone please help me with this calculus problem? I am very confused on how to complete it.
katrin2010 [14]

Answer:

cut into 6 parts

Step-by-step explanation:

4 0
3 years ago
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