Answer:
<em>Graph below</em>
Step-by-step explanation:
<u>Transformations</u>
Triangle ABC has coordinates A=(-4,2) B=(-2,6) C=(3,2)
We'll use the transformation (x,y) -> (2x, y+3) to map it to the triangle A'B'C'. Let's calculate the coordinates:
A'=(-8,5)
B'=(-4,9)
C'=(6,5)
The image below shows both triangles in the same grid
Answer:
2
Step-by-step explanation:
Please see attached picture for full solution.
The domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.
<h3>What is a function?</h3>It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have:
f(x) = 1/√x
m(x) = x² - 4
Domain of f(x)/m(x):
f(x)/m(x) = (1/√x)/(x² - 4)
f(x)/m(x) = 1/√x(x² - 4)
The denominator cannot be zero:
√x(x² - 4) ≠ 0
x(x - 2)(x+2) ≠ 0
x ≠ 0, 2, -2
and x > 0
Domain of f(x)/m(x) is: (0, ∞) - {0, 2, -2} or
Domain of f(m(x)):
f(m(x)) = 1/√(x² - 4)
x² - 4 > 0
Domain:
Domain of m(f(x)):
= ((1/√x)² - 4)
Domain:
Thus, the domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.
Learn more about the function here:
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