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skad [1K]
3 years ago
5

What is the y-intercept of the graph? A) (-2, 0) B) (2, 0) C) (0, -4) D) (0, 4)

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
8 0
(0,-4) I think is the correct answer for this problem
liraira [26]3 years ago
6 0
C. (0,-4) because that is the point where the line crosses the y axis. hope this helps!
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I don't understand the Pythagreon Therom, can someone explain how it works please? I have a test today.
Sholpan [36]

Answer:

Step-by-step explanation:

Pythagorean Theorem, is what provides us with the relationship between the sides in a right triangle. it is often written in the form of the equation: a2 + b2 = c2.

to work it out

5 0
3 years ago
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What is the equation in point-slope form of the line passing through (-1,3) and (1, 7)?
amid [387]

Answer:

<h3>y - 3 = 2(x+1)</h3>

Step-by-step explanation:

The equation of the line in point slope form is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is a point on the line

Get the slope;

Given the points (-1,3) and (1, 7)

m = y2-y1/x2-x1

m = 7-3/1+1

m = 4/2

m = 2

Substitute the point m = 2 and the point (-1, 3) into the formula above as shown;

y - y0 = m(x-x0)

y - 3 = 2(x-(-1))

y - 3 = 2(x+1)

Hence the required equation is y - 3 = 2(x+1)

3 0
3 years ago
sin un paquete de caramelos pesa 125g. ¿cuantos paquetes del mismo peso puedo formar con 5kg de caramelos?
MAVERICK [17]

40 paquetes

Step-by-step explanation:

5kg son 5000g, dividi por 125g

5000/125=40

8 0
3 years ago
Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.
Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have points (1,6) and (2,2)

Slope is:

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11

The equation of line will be:

y=mx+b\\y=-2x+11

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1

The equation of line will be:

y=mx+b\\y=\frac{1}{2}x+1

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

6 0
3 years ago
What is the solution to this system of equations
Gelneren [198K]

Answer:

-1,2

Step-by-step explanation:

just round and estimate and get nearest

4 0
3 years ago
Read 2 more answers
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