So let's say the amounts are "a" and "b", at 6% and 8% respectively.
how much is 6% of a?  well (6/100) * a, or 0.06a.
how much is 8% of b?  well (8/100) * b, or 0.08b.
so hmm whatever "a" and "b" amounts are, we know that their yield is $100, thus 
0.06a + 0.08b = 100.
now, there's more money in "a" than in "b", 500 bucks more, so whatever "b" is, we know that 
a = b + 500.

how much was deposited in the 6% one?  well, a = b + 500.
 
        
        
        
X/2 +3y = 6 . . . . . . . . starting point
x/2 = 6 -3y . . . . . . . . subtract terms that don't have x
x = 2(6 -3y) . . . . . . . . multiply by the inverse of the x-coefficient
x = 12 -6y . . . . . . . . . expand if you like
3y = 6 -x/2 . . . . . . . . subtract terms that don't have y
y = (6 -x/2)/3 . . . . . . . multiply by the inverse of the y-coefficient
y = 2 -x/6 . . . . . . . . . expand if you like
        
             
        
        
        
Answer:
c
Step-by-step explanation: