If temperature (T) and amount of gas (n) remain constant, but pressure (P) and volume (V) change, then the ideal gas law: PV = nRT becomes
P1V1 = P2V2 --> (41)(16) = P2 (4)
--> P2 (4) = 656
P2 = 656/4 = 164 kPa
The key concept you must have to remember is that, the rate is kept constant, as what is specified in the problem. Our basis for the rate is the first situation.
Rate = 20 facts/ 1 min.
Let's equate this to the second situation using x as the time unknown.
20/1 = 35/x
Solving for x,
<em>x = 1.75 minutes</em>
Your answer is B) 2.... .4 is tenths, .03 is hundredths, and .002 is thousandths
6hrs=72ft
12hrs=144ft
18hrs=216ft
24hrs=288ft
Answer = 288
