First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Tangerine is simply color orange, which is an addition of red and yellow colors. To analyze if the portions written below are reasonable, the given sum must equal to the sum of the individual red and yellow parts.
Total Red + Total Yellow = 5(3/10)
3(9/10) + 2(3/8) ? 5(3/10
3.45 ? 1.5
3.45 ≠ 1.5
<em>Since they are not equal, then it means the portions are unreasonable.</em>
All i know is that if the radius of a circle is 4 feet, the the diameter is 8 feet. Sorry, I don't know the rest.
Answer:
The student's current average score will be 69.2
Step-by-step explanation:
Let first test be TEST A: which is 20 of total and secures 62
Let second test be TEST B: which is 20 of the total marks and has secured 83.
Let third test be TEST C: which is 20 of total and has secured 91.
And now the TEST D which is 25 of total and has secured 88.
Therefore, by multipying across
= 12.4
= 16.6
= 18.2
=22
Now, by adding the scores to get the average score
We get, 69.2.
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
![\frac{99}{2} (2x+98)=p^3 \\ \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}](https://tex.z-dn.net/?f=%20%5Cfrac%7B99%7D%7B2%7D%20%282x%2B98%29%3Dp%5E3%20%5C%5C%20%20%5C%5C%2099x%2B4%2C851%3Dp%5E3%5C%5C%20%5C%5C%20%5CRightarrow%20x%3D%5Cfrac%7Bp%5E3-4%2C851%7D%7B99%7D)
By substitution, we have that
![p=33](https://tex.z-dn.net/?f=p%3D33)
and
![x=314](https://tex.z-dn.net/?f=x%3D314)
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>