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Naddika [18.5K]
4 years ago
6

Which rule represents the reduction of a figure?

Mathematics
1 answer:
Stella [2.4K]4 years ago
5 0

Answer:Dilate the figure by a scale factor of 5 with the origin as the center of dilation. What are ... Q. A dilation can produce a larger figure also called a(n)______. answer choices. reduction. enlargement ... Q. Which rule represents the dilation shown

Step-by-step explanation:

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Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
3 years ago
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What is the image of (0,-8)(0,−8) after a reflection over the line y=-xy=−x?
AnnZ [28]

Answer:

(8, 0 )

Step-by-step explanation:

under a reflection in the line y = - x

a point (x, y ) → (- y, - x ) , then

(0, - 8 ) → (8, 0 )

5 0
2 years ago
PLEASE HELP WITH THIS ONE AS WELL! I’m struggling with Transcendental Functions!
Svetach [21]

h(x)=20e^{kx}

a. If h(1)=20, then 20=20e^k\implies e^k=1\implies k=0.

b. If h(1)=40, then 40=20e^k\implies e^k=2\implies k=\ln2, so that 2k+1=2\ln2+1.

c. If h(1)=10, then 10=20e^k\implies e^k=\dfrac12\implies k=-\ln2, so that k-3=-\ln2-3.

3 0
3 years ago
What is the scale factor from the original design to the enlarged design?
bazaltina [42]
The answer is 2 due to the fact that 2 is even, and can be added more than once.
5 0
3 years ago
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I really need help it looks simple but i have no clue please helpppp no links :((
Alexus [3.1K]

Answer:

420 in³

Step-by-step explanation:

14 x 10 x 3 = 420

5 0
3 years ago
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