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katovenus [111]
3 years ago
9

What is the area of this figure

Mathematics
2 answers:
vodomira [7]3 years ago
5 0

area = 4 \times 4  +  \frac{4 \times 6}{2}   \\ = 16 + 12 = 28 \:  {yd}^{2}

Alla [95]3 years ago
5 0

~Hello There!~

area of triangle = \frac{b *h}{2}

area of triangle = \frac{6*8}{2}

area of triangle = 24

area of square = b*h

area of square = 4 * 4

area of square = 16

total area = 24 + 16

total area = 40yd^{2}

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

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Answer:

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Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

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\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

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Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

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x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

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~Kk

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