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3 years ago

18. Ten students from a school appear in one or more subjects for an inter school

Mathematics

2 answers:

Alja [10]3 years ago

8 0

Answer:

Step-by-step explanation:

(G n m) = [Max, Anael]

(G u S) = [Acel, Action, Anael, Max, Carl, Dario, Carlin, Kia, Barak]

abruzzese [7]3 years ago

5 0

Answer:

(G n M) = [Max, Anael]

(G u S) = [Acton, Anael, Dario]

Step-by-step explanation:

(G n M) in yellow

(G u S) in green

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Write the following expression. The quantity 81 minus 5k, squared

Stella [2.4K]

Answer:

81-25k²

Step-by-step explanation:

We need to write the expression for "The quantity 81 minus 5k, squared".

Square of any number x is given by x².

Square of 5k is given by : (5k)²= 5²×k²=25k²

Now subtract 25k² from 81.

It means we get : 81-25k². It is required expression.

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3 years ago

The roof of the building shown below has a span of 48 feet. The rafters upon which the roof is laid are 30 feet long, including

anyanavicka [17]

Solution :

Given :

Span of the roof = 48 feet

Length of the rafter = 30 feet (including the 4 feet overhung)

So, for the 30 feet long rafter, 26 feet will be rafter length from the high point of the roof to the edge of the roof and 4 feet will be the roof overhung.

Therefore, the horizontal span per rafter is

$=\frac{48}{2}$

= 24 feet

a). So the rise of the roof is $= \sqrt{(26)^2-(24)^2}$

= 10 feet

b). Pinch of the roof is $=\frac{\text{rise}}{\text{run}}$

$=\frac{10}{24}$

$=\frac{5}{12}$

c). The percent of the roof used as overhung is

$=\frac{4+4}{60}\times 100$

$=\frac{80}{6}$

= 13.33 %

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2 years ago

Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan

inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

$P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}$

$= \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \ \ \\\\$

$k= 2,3..........10$ For option B:

$P(X=k | X \geq 2 ) = \sum^{10}_{i=2} \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}$

$k= 2,3, 4.........10$

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3 years ago

Charlie is watching hot air balloons. Balloon A has risen at a 60° angle. Balloon B has risen at an 82 angle. If the distance fr

Karo-lina-s [1.5K]

Step-by-step explanation:

b is the anwser or 1005 so there u go

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2 years ago

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2x(6x^2 + 3x - 1)<br><br> Simplify

likoan [24]

Answer: 12x^3+ 6x^2- -2x

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2 years ago