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Alexandra [31]
3 years ago
13

18. Ten students from a school appear in one or more subjects for an inter school

Mathematics
2 answers:
Alja [10]3 years ago
8 0

Answer:

Step-by-step explanation:

(G n m) = [Max, Anael]

(G u S) = [Acel, Action, Anael, Max, Carl, Dario, Carlin, Kia, Barak]

abruzzese [7]3 years ago
5 0

Answer:

(G n M) = [Max, Anael]

(G u S) = [Acton, Anael, Dario]

Step-by-step explanation:

(G n M) in yellow

(G u S) in green

You might be interested in
The difference of two supplemtary angles is 58 degrees. Find the measures of the angles
erik [133]

Answer:

The measure of the angles are 61° and 119°

Step-by-step explanation:

Let the first angle = x°

let the second angle = y°

The sum of two supplementary angles = 180°

x° + y° = 180° ----- equation (1)

based on the given question; "the difference of two supplementary angles is 58 degrees."

x° - y° = 58° ------- equation (2)

from equation (2), x° = 58° + y°

Substitute the value of x into equation (1)

(58° + y°) + y° = 180°

58 + 2y = 180

2y = 180 -58

2y = 122

y = 122 / 2

y = 61°

The second angle is given by;

x° = 58° + y°

x = 58° + 61°

x = 119°

Thus, the measure of the angles are 61° and 119°

4 0
3 years ago
8% of the employees at a shop work part-time.
nikitadnepr [17]

There are 50 employees in total

<h3>How to determine the total employee?</h3>

The given parameter is:

Part-time = 8% of total employee

Rewrite as:

Part-time = 8% * total employee

There are 4 part-time employees.

So, we have:

8% * total employee = 4

Divide both sides by 8%

total employee = 50

Hence, there are 50 employees in total

Read more about percentage at:

brainly.com/question/843074

#SPJ1

7 0
2 years ago
The length of a rectangle is 3cm more than the width. The area is 70cm^2. Find the dimensions of the rectangle​
Rom4ik [11]
Let width be x
Length would be x + 3
Area = L * W
Make an equation
(x) * (x+3) = 70
x^2 + 3x = 70
x^2 + 3x - 70 = 0
Quadratic formula
(-3 +/- rt 3^2 - 4 * 1 * (-70))/(2 * 1)
x1 = (-3 + 17)/2, x2 = (-3-17)/2
x = 7, x = -10
Dimension cannot be negative

Solution: width = 7
Length = 10
7 0
2 years ago
Suppose J is between H and K. Use the Segment Addition Postulate to solve for x, HJ,
Kisachek [45]
I love the green bean and the national
6 0
3 years ago
S=1+2+3+........+100
nordsb [41]

Answer:

5050

Step-by-step explanation:

Gauss has derived a formula to solve addition of arithmatic series to find the sum of the numbers from 1 to 100 as follows:

1 + 2 + 3 + 4 + … + 98 + 99 + 100

First he has splitted the numbers into two groups (1 to 50 and 51 to 100), then add these together vertically to get a sum of 101.

1 + 2 + 3 + 4 + 5 + … + 48 + 49 + 50

100 + 99 + 98 + 97 + 96 + … + 53 + 52 + 51

1 + 100 = 101

2 + 99 = 101

3 + 98 = 101

:

:

:

:

48 + 53 = 101

49 + 52 = 101

50 + 51 = 101

It was realized by him that final total will be fifty times of 101 means:

50(101) = 5050.

Based on this, Gauss has derived formula as:

The sequence of numbers (1, 2, 3, … , 100) is arithmetic and we are looking for the sum of this series of sequence. As per Gauss, the special formula derived by him can be used to find the sum of this series:

S is the sum of the series and n is the number of terms in the series, in present case, from 1 to 100, Hence

As per the Gauss formula, the sum of numbers from 1 to 100 will be 5050.

Answer : 5050

4 0
2 years ago
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