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SashulF [63]
2 years ago
15

What is the slope of a line perpendicular to the line whose equation is 4x+5y=35. Fully simplify your answer.

Mathematics
1 answer:
grin007 [14]2 years ago
5 0

Answer:

The slope a line perpendicular to the line whose equation is 4x+5y=35, is \frac{5}{4}.

Step-by-step explanation:

1. Solve the given equation for y.

4x+5y=35\\\\5y=35-4x\\\\\frac{5y}{5} =\frac{35}{5} -\frac{4x}{5} \\\\y =7 -\frac{4x}{5}\\\\y = -\frac{4}{5}x+7

2. Identify the slope.

The slope of a linear equation is always the number x is being multiplied for. Hence, the value of this equation is -\frac{4}{5} .

3. Find the slope of the perpendicular line.

The slope of a perpendicular line is always the multiplicative and addition reciprocal of the initial function. This means that you will have to invert and fracction, and add the inverse sign before it. Let's do it by parts:

a) Find the multiplicative reciprocal (invert the fraction).

-\frac{5}{4}

b) Put the opposite sign before the fraction.

+\frac{5}{4}

4. Express a result.

The slope a line perpendicular to the line whose equation is 4x+5y=35, is \frac{5}{4}.

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3 years ago
Sami's bank account earns 4% simple interest per year. If Sami deposits $500, how much simple interest will she earn in four yea
Oksanka [162]

Answer:

20

Step-by-step explanation:

1% of 500 is 5

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3 0
3 years ago
supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are
Simora [160]
<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu

, where n= sample size

\overline{x} = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : df=n-1=24

\overline{x}= \$93.36

s=\ $19.95

Significance level for 98% confidence interval : \alpha=1-0.98=0.02

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu

=93.36-9.943878< \mu

=93.36-9.943878< \mu

=83.416122< \mu

Hence, the 98% confidence interval for the mean repair cost for the dryers. = 83.4161

4 0
3 years ago
The slope field for the differential equation dy/dx=(3y)/(xy+5x) will have vertical segments when
Inessa05 [86]

Answer:

E) x=0 or y=-5

Step-by-step explanation:

The slope field will have vertical segments when dy/dx is undefined, that is, dy/dx is a division by 0.

We have that

dy/dx=(3y)/(xy+5x)

So the slope field will have vertical segments when

xy + 5x = 0

x(y + 5) = 0

This is when x = 0 or y = -5.

So the correct answer is:

E) x=0 or y=-5

3 0
3 years ago
What is the sale price for your purchase if you have a 20% off coupon and you buy a shirt for $19.99 and pants for $10.
Andrew [12]
Answer: I believe it is $23.99

Explanation:
19.99+10= 29.99
29.99x0.2= 5.992
29.99-5.99= $23.99

I hope this helped!
4 0
3 years ago
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