Find the amount of the discount on a $234 item with a discount of 15%
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The first evening she received x calls.
The second evening she received 7 fewer calls than the first evening, so she received x-7 calls.
The third evening she received 3 times as many calls as the first evening, so she received 3x calls.
Over the three evenings she received 73 calls altogether.
The first evening she received 16 calls, the second evening she received 9 calls, the third evening she received 48 calls.
The second evening she received 7 fewer calls than the first evening, so she received x-7 calls.
The third evening she received 3 times as many calls as the first evening, so she received 3x calls.
Over the three evenings she received 73 calls altogether.
The first evening she received 16 calls, the second evening she received 9 calls, the third evening she received 48 calls.
Answer:
Step-by-step explanation:
<u>Perpendicular lines</u>
Perpendicular lines have slopes whose product is -1. In other words, to find a line that is perpendicular to a given line, the new line must have a that is the opposite reciprocal of the original line.
<u>Passing through a point</u>
Additionally, if a line contains a point, then the point must be a solution to the equation (meaning, when you plug in the "x" and "y", the equation must be true).
<u>Finding our perpendicular line</u>
<u>Work on slope first</u>
To find the slope of the original line, rewrite the original line in slope-intercept form:
In this form, the slope is the number multiplied to the "x", so the original slope is -3/1.
Thus, the slope of the new perpendicular line will be the opposite reciprocal of -3/1 ... which is 1/3.
Writing what we do know about the new perpendicular line, we have
<u>Making sure it passes through the point</u>
This new line is also supposed to contain the point (-3,-1), so (-3,-1) must be a solution to the equation, for whatever constant-value the "b" is. To find out the "b", substitute the known quantities, and solve:
Substituting this into our equation:
<u>Conclusion</u>
So, the equation for a line that is perpendicular to the original line , and that also passes through (-3,-1) is