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Vaselesa [24]
3 years ago
13

Ann, Jim, and Miguel sent a total of 115

Mathematics
1 answer:
FromTheMoon [43]3 years ago
3 0
Ann: 21
Jim: 31
Miguel: 63



Let’s start by finding Ann’s number.

a + (a + 10) + 3a = 115

5a + 10 = 115

5a = 115 - 10

5a = 105

a = 105 / 5

a = 21

Now, just find the others’ numbers using Ann’s.

Jim sent ten more messages than Ann, and 21 + 10 = 31.

Miguel sent 3 times as many messages as Ann, and 21 * 3 = 63.
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