Question

Ann, Jim, and Miguel sent a total of 115

Answer 1

Ann: 21
Jim: 31
Miguel: 63



Let’s start by finding Ann’s number.

a + (a + 10) + 3a = 115

5a + 10 = 115

5a = 115 - 10

5a = 105

a = 105 / 5

a = 21

Now, just find the others’ numbers using Ann’s.

Jim sent ten more messages than Ann, and 21 + 10 = 31.

Miguel sent 3 times as many messages as Ann, and 21 * 3 = 63.