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Natali5045456 [20]
3 years ago
15

If you need 8 oz of chocolate chips to make 1.6 lb of cookie dough how many ounces of chocolate chips will you need to make 7 lb

of cookie dough
Mathematics
1 answer:
iren [92.7K]3 years ago
6 0

Answer:

3.5 Oz of chocolate

Step-by-step explanation:

1.6 lb of cookie dough is made from chocolate of 8 Oz

1 lb will be made by 8/ 1.6 = 0.5 Oz of chocolate

Therefore

7lb of cookie dough will be made from 7 * 0.5= 3.5 Oz of chocolate/

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A triangle's height is 10 feet more than its base. If the area of the triangle is 100 square feet, use factoring to find its dim
stiks02 [169]

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

Step-by-step explanation:

Height = base + 10

Area = 100 square ft

Area of a triangle= (1/2) (b) (h)

100 = (1/2) (b) (b + 10)

200 = b(b) + 10b

b(b) + 10b - 200 = 0

b(b) + 20b - 10b - 200 = 0

b ( b + 20) -10(b + 20) = 0

(b-10) (b+20) =0

b = 10 (or) b = -20

Here b is the length and cannot be negative.

So, b = 10ft

h = b + 10

h = 10 + 10

h = 20 ft.

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

6 0
3 years ago
Is 50,997,850 divisible by 3?
Rufina [12.5K]

Answer:

16,999,283

Step-by-step explanation:

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3 years ago
Does -3(x-4)= -3x=12 have one solution, many solutions, or no solutions at all?
TEA [102]

Answer:

If the expression is:

-3x + 12 = -3x + 12, infinite solutions

If the expression is:

-3x + 12 = -3x - 12, no solutions

Step-by-step explanation:

Step 1: Distribute

-3x + 12 = 3x = 12

If both lines have the same slope and same y-int, they are the same line and therefore have infinite solutions.

If both lines have the same slope but different y-int, then they are parallel and therefore have no solutions.

4 0
3 years ago
Find the geometric of 5,8,9,12,15​
Rudik [331]

Answer:

mom this u?

Step-by-step explanation:

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Given: AC and BD bisect each other.<br> Prove: AB | CD and BC || AD.
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2) \overline{AE} \cong \overline{EC} (a segment bisector splits a segment into two congruent parts)

3) \overline{BE} \cong \overline{ED} (a segment bisector splits a segment into two congruent parts)

4) \angle AEB \cong \angle CED (vertical angles are congruent)

5) \triangle BEA \cong \triangle DEC (SAS)

6) \angle EBA \cong \angle EDC (CPCTC)

7) \overline{AB} \parallel \overline{CD} (converse of alternate interior angles theorem)

8) \angle BEC \cong \angle AED (vertical angles are congruent)

9) \triangle BEC \cong \triangle DEA (SAS)

10) \angle ECB \cong \angle EAD (CPCTC)

11) \overline{BC} \parallel \overline{AD} (converse of alternate interior angles theorem)

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