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GuDViN [60]
3 years ago
5

Which of the following best describes the relationship shown in the equation below?

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0
Neither jajsjxkkskxldodkkdosodjdjdjd
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Can someone please help me I really need help it’s my last question
Svetach [21]

Answer:

x^2+11x+30

Step-by-step explanation:

This is a parallelogram.

Area of a parallelogram can be found with:

A=bh

Plug our values in.

A=(x+6)(x+5)

FOIL-

First: x*x=x^2

Outside: x*5=5x

Inside: 6*x=6x

Last: 6*5=30

x^2+5x+6x+30

Combine like terms.

x^2+11x+30

7 0
2 years ago
Determine which statement is true about the zeros of the function graphed below.
Oksi-84 [34.3K]
The real solution occurs when the graph intersects the x axis,

In the problem shown, the graph does not intersect the x axis, therefore it has no real solution, this means that the answer must have a complex conjugate pair

The answer is
function f has exactly two complex solutions
4 0
3 years ago
Read 2 more answers
{ x + y = 158<br> x- y = 112
ZanzabumX [31]

Answer:

i have know

Step-by-step explanation:

3 0
2 years ago
A car sells for 16,000. If the rate of depreciation is 18%, find the value of the car after 8 years.
Black_prince [1.1K]

Answer:

Step-by-step explanation:

price after 8 years Amount=P(1-0.18)^8

Amount=16,000(1-0.18)^8

=16,000(0.82)^8

≈3270.63 $

6 0
3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
Read 2 more answers
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