Answer:

Step-by-step explanation:
Answer:
(4.65 x 10)^3 = 100,544.625
Step-by-step explanation:
First, multiply 4.65 by 10
46.5
Now multiply this number by itself 3 times
46.5 x 46.5 = 2,162.25
2,162.25 x 46.5 = 100,544.625
So the answer is 100,544.625
Hope this helps :)
Answer:
The probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Step-by-step explanation:
Let <em>X</em> = number of household owns a sports car.
The probability of <em>X</em> is, P (X) = p = 0.07.
Then the random variable <em>X</em> follows a Binomial distribution with <em>n</em> = 3 and <em>p</em> = 0.07.
The probability function of a binomial distribution is:
![P(X=x) = {n\choose x}p^{x}[1-p]^{n-x}\\](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20%7Bn%5Cchoose%20x%7Dp%5E%7Bx%7D%5B1-p%5D%5E%7Bn-x%7D%5C%5C)
Compute the probability that of the 3 households randomly selected at least 1 owns a sports car:

Thus, the probability that of the 3 households randomly selected at least 1 owns a sports car is 0.1956.
Answer:
depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
Step-by-step explanation:
- First calculate the amount of depreciation/ton
- depreciation per ton = $125,000/208,000 = $0.600 /ton
- Hence depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
Answer:
x= 0, -1
Step-by-step explanation: