Given:
The vertices of a polygon are A (−1, 1), B (4, 1), C (4,−2), and D(−1,−2).
To find:
The perimeter of ABCD.
Solution:
Distance formula:
Using distance formula, we get
Similarly,
Now, perimeter of ABCD is
Therefore, the perimeter of ABCD is 16 units.
Answer:
<h3>The answer is option B</h3>
Step-by-step explanation:
The nth term of the sequence is
A(n) = 5n + 7
To find the (n+1)st term substitute n+1 into the general equation
That's
<u>For (n + 1)st term</u>
A(n+1) = 5(n+ 1) + 7
A(n+1) = 5n + 5 + 7
<h3>A(n+1) = 5n + 12</h3>
Hope this helps you
Answer:
Its 102.5
Step-by-step explanation:
Answer:
length = 235 yd
width = 58 yd
Step-by-step explanation:
Let the width be W.
L = 4W + 3
perimeter = 2(L + W)
perimeter = 2(4W + 3 + W)
perimeter = 2(5W + 3) = 10W + 6
We are told the perimeter = 586 yd
10W + 6 = 586
10W = 580
W = 58
L = 4W + 3 = 4(58) + 3 = 232 + 3 = 235
length = 235 yd
width = 58 yd
