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Pavlova-9 [17]
3 years ago
7

How does one solve for the n+1st term with the nth term of a sequence

Mathematics
2 answers:
love history [14]3 years ago
4 0

Answer:

<h3>The answer is option B</h3>

Step-by-step explanation:

The nth term of the sequence is

A(n) = 5n + 7

To find the (n+1)st term substitute n+1 into the general equation

That's

<u>For (n + 1)st term</u>

A(n+1) = 5(n+ 1) + 7

A(n+1) = 5n + 5 + 7

<h3>A(n+1) = 5n + 12</h3>

Hope this helps you

pav-90 [236]3 years ago
3 0

n^{\text{th}} \text{ term is } 5n+7

forget <em>n</em> for a while.

let's call it <em>t</em><em> </em>.

The t^{\text{th}} \text{ term is } 5t+7

agreed? I don't think there should be a problem.

you're asked what's the (t+1)^{\text{th}} term.

let's call it <em>u</em><em> </em><em>.</em><em> </em> so just like we did before,

u^{\text{th}} \text{ term is } 5u+7

but we know, u=t+1

So, 5u+7=5(t+1)+7=5t+12

does that answer your question?

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