Answer:
3x^2+27y^2-18xy
Step-by-step explanation:
3(x-3y)^2
3 [(x-3y)(x-3y)]
3 [x^2-3xy-3xy+9y^2]
3 [x^2-6xy+9y^2]
open d bracket
3x^2-18xy+27y^2
rearrange
3x^2+27y^2-18xy
Answer:
It is a function.
Step-by-step explanation:
Functions are relations in which one domain value is assigned to exactly one range value. The x-value must not repeat in the relation set for it to be a function.
{(2,3), (4,3), (6,3), (5,9), (3,9)}
There are no repeating x-values given.
The relation should be a function.
Hope this helps.
12=x ! Just subtract 3 from both sides.
Answer:
82 in^3
Step-by-step explanation:
3 x 2 x 7 + 2 x 2 x 10 = 82 in^3
