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Gennadij [26K]
2 years ago
7

What is the volume of this?

Mathematics
1 answer:
Oksanka [162]2 years ago
7 0

Answer:

82 in^3

Step-by-step explanation:

3 x 2 x 7      + 2 x 2 x 10    =  82 in^3

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I think he 2nd one because u add unlike together and get 5 and you put - in front of the 9
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3 years ago
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What is the answer to this equaction-8c+8=5c+2
Lyrx [107]

Answer: c=-2

Step-by-step explanation:

4 0
3 years ago
The management of Acrosonic plans to market the ElectroStat, an electrostatic speaker system. The marketing department has deter
crimeas [40]

Answer:

(a)R(x)=-0.02x^2+610x

(b)R'(x)=-0.04x+610

(c)R'(5400)=$394

Step-by-step explanation:

Given that x is the quantity demanded and the speaker's unit price (in dollars) is p where:

p = −0.02x + 610 (0 ≤ x ≤ 20,000)

(a)Revenue function R.

Revenue = Price X Quantity Demanded

Therefore:

R(x)=xp

=x(-0.02x + 610)\\R(x)=-0.02x^2+610x

(b)Marginal revenue function R'(x)

If R(x)=-0.02x^2+610x

Then, the marginal revenue function

R'(x)=-0.04x+610

(c)We want to compute R'(5,400)

R'(5400)=-0.04(5400)+610\\R'(5400)=394

From the above, we can infer that the revenue that will be generated on the sales of the 5401st item is $394.

5 0
3 years ago
The formula for the surface area of a cylinder is A=2πr(r+h).Find h if A=80π and r=5.
lesya [120]
A=2<span>πr(r+h)
</span>80π=<span>2π(5)(5+h)
</span>80π=10π(5+h)
80π=50π + 10πh
30π=10πh
3=h
3 0
3 years ago
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
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