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3 years ago

41 out of 50 women surveyed liked perfume. what percentage of women did NOT like perfume

Mathematics

2 answers:

Vinil7 [7]3 years ago

8 0

Answer

18% of women do not like perfume.

Step-by-step explanation:

First do 50-41, which is 9 to find out how many women don't like perfume. Next you find the percentage by doing 9/50 = 0.18 then you multiply 0.18 by 100. Finally you get 18%.

krok68 [10]3 years ago

3 0

Answer:

18%

Step-by-step explanation:

Long Version: 41/50 = 0.82 and when you move the decimal two places right, you will get 82%. 100%-82%= 18%

Short Version: 9/50 people didn't like perfume. 9/50= 0.18 then you move the decimal two places right and it becomes 18%.

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A certain article indicates that in a sample of 1,000 dog owners, 610 said that they take more pictures of their dog than of the

lbvjy [14]

Answer:

(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).

(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).

(c) First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

Step-by-step explanation:

(a)

Let X = number of dog owners who take more pictures of their dog than of their significant others or friends.

Given:

X = 610

n = 1000

Confidence level = 90%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{610}{1000}=0.61$

The critical value of z for a 90% confidence level is:

$z_{\alpha/2}=z_{0.10/2}=z_[0.05}=1.645$

Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.61\pm 1.645\sqrt{\frac{0.61(1-0.61}{1000}}\\=0.61\pm 0.015\\=(0.595, 0.625)\\\approx(0.60, 0.63)$

Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).

Interpretation:

There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).

Correct option is (3).

(b)

Let X = number of dog owners who are more likely to complain to their dog than to a friend.

Given:

X = 440

n = 1000

Confidence level = 95%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{440}{1000}=0.44$

The critical value of z for a 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.44\pm 1.96\sqrt{\frac{0.44(1-0.44}{1000}}\\=0.44\pm 0.016\\=(0.424, 0.456)\\\approx(0.42, 0.46)$

Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend is (0.42, 0.46).

Interpretation:

There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).

Correct option is (1).

(c)

The confidence interval in part (b) is wider than the confidence interval in part (a).

The width of the interval is affected by:

The confidence level
Sample size
Standard deviation.

The confidence level in part (b) is more than that in part (a).

Because of this the critical value of z in part (b) is more than that in part (a).

Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.

First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

4 0

3 years ago

If Chung's go-kart can travel 48 miles on 1 gallon of gas, how far can his go-kart travel on 1.15 gallons of gas?

Nataliya [291]

So to get the answer you multiply 48 by 1.15 and you get 55.2
Chung's go-kart can travel 55.2 miles on 1.15 gallons of gas.

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3 years ago

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Slope intercept for (0,4) (-5,0)

ruslelena [56]

Answer:

y = 0.8x + 4

Step-by-step explanation:

The slope is 0.8 and y intercept is 4.

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3 years ago

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This rectangle is half as wide as it is long what is the perimeter of the rectangle

kramer

length=4 cm width=2 cm

4(2)+2(2)=12

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3 years ago

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The ratio of money in Terry's bank account to Faye's bank account was 3:7.

igor_vitrenko [27]

Answer:

£390

Step-by-step explanation:

The ratio of money in bank:

Terry : Faye

3 : 7

Terry put £220 in his account

Faye withdrew £300 from her account

Unknown:

Initial amount Terry had = ?

Solution:

Let the real amount terry has = 3x

Faye will have = 7x

Now;

3x + 220 = 7x -300

Solving this equation:

3x + 220 = 7x -300

3x - 7x = -300 - 220

-4x = - 520

4x = 520

x = 130

Originally, Terry has 3x = 3 x 130 = £390

3 0

3 years ago

41 out of 50 women surveyed liked perfume. what percentage of women did NOT like perfume​

41 out of 50 women surveyed liked perfume. what percentage of women did NOT like perfume