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3 years ago

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A determined gardener has 120ft of deer-resistant fence. She wants to enclose a rectangular vegetable garden in her backyard, an

d she wants the area that is enclosed to be at least 800 square feet. What range of values is possible for the length of her garden?

1 answer:

Pavlova-9 [17]3 years ago

3 0

Answer:

the answer is 123

Step-by-step explanation:

cuz thats wat it is cux i think so

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A random sample of 500 reports an average yearly income of $42,000 with a standard deviation of $1000. An estimate of the parame

Lorico [155]

Answer:

E

Step-by-step explanation:

Confidence Interval = mean + or - error margin

Mean = 42,000, error margin = width of estimate of the parameter ÷ 2 = 175 ÷ 2 = 87.50

We can be 95% confident that the population mean is 42,000 plus or minus 87.50

8 0

3 years ago

The table shows the distance in feet, y, that a rocket traveled in x seconds.

Murrr4er [49]

Answer:

The correct option is D. y = 25 $x^{2}$ .

Step-by-step explanation:

i) From the table and our own observation and a trial and error approach we

can clearly see that the equation that matches y in feet ( the distance

traveled by the rocket) and x in seconds ( the time elapsed) is given by the

equation y = 25 $x^{2}$

Therefore the correct option is D. y = 25 $x^{2}$ .

7 0

3 years ago

Read 2 more answers

Randy won 36 out of 54 games of tic tac toe. what percent of the games did he win

Archy [21]

36/54 = x/100

54x = 100 * 36
54x = 3600
x = 3600 ÷ 54
x = 66.666666.... so 66.67

First put it into a proportion and then cross multiply. After that you divide both sides by 54 to get x alone which gives you 66.66666 which is rounded to 66.67

Answer: 66.67%

7 0

3 years ago

Read 2 more answers

Estimate the sum 8/10 + 1/9

RideAnS [48]

Answer:

41/45

Step by Step Explanation:

Add: 8/

10

+ 1/

9

= 8 · 9/

10 · 9

+ 1 · 10/

9 · 10

= 72/

90

+ 10/

90

= 72 + 10/

90

= 82/

90

= 2 · 41/

2 · 45

= 41/

45

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(10, 9) = 90. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 10 × 9 = 90. In the following intermediate step, cancel by a common factor of 2 gives 41/

45

.

In other words - eight tenths plus one ninth = forty-one forty-fifths.

8 0

2 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago