Answer:
I found two different solutions. Hope one of them help!
1. x = -1/3 = -0.333
2. x = 5/2 = 2.500
Step-by-step explanation:
13 ± √ 289
x = ——————
12
Can √ 289 be simplified ?
Yes! The prime factorization of 289 is
17•17
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 289 = √ 17•17 =
± 17 • √ 1 =
± 17
So now we are looking at:
x = ( 13 ± 17) / 12
Two real solutions:
x =(13+√289)/12=(13+17)/12= 2.500
or
x =(13-√289)/12=(13-17)/12= -0.333
Two solutions were found :
x = -1/3 = -0.333
x = 5/2 = 2.500
Step-by-step explanation:
1. you set each expression equal to 0.
x-7=0 and x+3=0
2. Next you need to get the variable by itself so you would add 7 to both sides on the first equation and subtract 3 from both sides for the second one.
3. So your answers would be x=7 and x=-3. Those are the zeros.
X+3y=7
x-3y=1
add them together
x+3y=7
<u>x-3y=1 +
</u>2x+0y=8
2x=8
divide 2
x=4
subsitute
x+3y=7
4+3y=7
subtract 4
3y=3
divid 3
y=1
x=4
y=1
answer is A
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Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
x = w/3 - 2/3
