This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Answer:
If problem is "-|2x+3|+8=12"
then there is (<em>no solution.)</em>
Step-by-step explanation:
Let's solve your equation step-by-step.
−|2x+3|+8=12
Step 1: Add -8 to both sides.
−|2x+3|+8+−8=12+−8
−|2x+3|=4
Step 2: Divide both sides by -1.
−|2x+3|=4
-1 -1
|2x+3|=−4
Step 3: Solve Absolute Value.
|2x+3|=−4
No solutions Because absolute value is less than 0.
Step-by-step explanation:
3 and 4.
because the sum of the smaller two sides of a triangle have to be less than or equal to the 3rd larger side.
<h2>
Answer:The graph of
is the graph of
compressed vertically.</h2>
Step-by-step explanation:
Given that 
and 
is always positive because 
is always positive.
is always positive because 
is always positive.
So,both are always positive.
So,there is no flipping over x-axis.
In ,the height of a point at 
is 
In ,the height of a point at is 
So,height of any point has less height in than
So,the graph of is the graph of compressed vertically.
