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3 years ago

-What is the value of the expression:7-1.0+3÷3

Mathematics

2 answers:

bixtya [17]3 years ago

5 0

Answer:

Step-by-step explanation:

This problem deals with order of operations. If you solve the problem from left to right, you will get an incorrect answer. Instead recall PEMDAS.

Parentheses first

Exponents

Multiplication and Division (left-to-right)

Addition and Subtraction (left-to-right)

We start with the division, as there are no parentheses or exponents. 3÷3=1.

Now we can replace the 3÷3 with a 1 in the expression.

7-1.0+1

Since we only have addition and subtraction left, we now proceed from left to right.

7-1.0=6, and 6+1=7.

7-1.0+1=7.

Therefore, the answer is 7.

liberstina [14]3 years ago

3 0

Answer:

Step-by-step explanation:

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Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.